Help with bar model.

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# Question

# Answer

As sushi88 mentioned, the phrasing of the question is ambiguous. In my answer below, I am assuming it is: "On the second day, he spent 1/4 of hisremainingmoney...". The amount left of $6.40 is equal to 1 small blue unit. So at the end of Day 1, we have 8 blue units = 8 x 6.4 = $51.20. Add $4 to get 3/4 of starting amount = $55.20So amount of money he had at first is 55.20 * 4/3 = $73.60.

@mr.tan, it has to be one of those typo errors that we have stated, either a missing word or a number typed wrongly. *high-five*

However, I won’t say the question is ambiguous. It is erroneous. Ambiguous means possibly more than one answer. Erroneous means the question actually cannot be solved at all. lol Sorry I am also particular about English. lol

This question cannot be solved because the numbers are incorrect.

Say, let original amount of money be 4u

Total money [ u ][ u ][ u ][ u ]

[ Spent ][ 2 bx tea ][ 2 bxs tea ][ 2 bxs tea ][1bx tea][$4 misplaced][6.40]

If 2 boxes tea = u, 5 boxes = 2.5u

So there is not enough money for the 5th box of tea and the $4 misplaced, how to have $6.40 left over?

Question has “Money not enough” … it cannot be solved.

However, if I change **3rd day buy 3 boxes of tea.**..then it is possible.

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**Solution after the change:**

Total money [ u ][ u ][ u ][ u ]

[ Spent ][ 2 bx tea ][ 2 bxs tea ][tea][$4][6.4]

2 boxes tea —> u => 1 box = u/2 = 0.5u

u = 0.5u + 4+ 6.4

0.5u = 10.4

u = 20.8

Hence total money = 4u = 4(20.8) = $83.20

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