The ratio of the number of marbles Kaden, Adam, and John gave away was 2:4:9. The number of marbles Kaden have away was 2 fewer than the number of marbles he had left. Adam had 1/2 as many marbles left as John. Kaden had 1/2 as many marbles left as Adam. They had a total of 56 marbles left. How many marbles did John give away?

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# Answer

sushi88

Kaden Adam John

Gave away 2u 4u 9u

Marbles left **2u+2 ** 2(2u+2)=**4u+4** 2(4u+4)=**8u+8**

**( give away 2 fewer than left**) (**K 1/2 as many left as A**) (**A 1/2 as many left as J**)

**2u+ 2 + 4u+4 **+ **8u + 8** = 56

14u =56 -14 = 42

u= 3

Hence John gave away 9×3 = 27 marbles

mr.tan

Is there a typo? “The number of marbles Kaden **have away **was 2 fewer than the number of marbles he had left. ” I assume it is “gave away”.

Suppose Kaden had u marbles left. Then Adam had 2u left and John 4u left. So total left = u + 2u + 4u = 7u = 56 and thus u = 56/7 = 8. Kaden gave away 8 - 2 = 6 marbles.John gave away 6 / 2 * 9 = 27 marbles.CHECKKaden Adam John Gave 6 12 27 (6:12:27 = 2:4:9) Left 8=2+6 16 32 (sum = 56)

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