The ratio of the number of marbles Kaden, Adam, and John gave away was 2:4:9. The number of marbles Kaden have away was 2 fewer than the number of marbles he had left. Adam had 1/2 as many marbles left as John. Kaden had 1/2 as many marbles left as Adam. They had a total of 56 marbles left. How many marbles did John give away?
STUCK ON HOMEWORK?
ASK FOR HELP FROM OUR KIASUPARENTS.COM COMMUNITY!
Question
Answer
sushi88
Kaden Adam John
Gave away 2u 4u 9u
Marbles left 2u+2 2(2u+2)=4u+4 2(4u+4)=8u+8
( give away 2 fewer than left) (K 1/2 as many left as A) (A 1/2 as many left as J)
2u+ 2 + 4u+4 + 8u + 8 = 56
14u =56 -14 = 42
u= 3
Hence John gave away 9×3 = 27 marbles
mr.tan
Is there a typo? “The number of marbles Kaden have away was 2 fewer than the number of marbles he had left. ” I assume it is “gave away”.
Suppose Kaden had u marbles left. Then Adam had 2u left and John 4u left.
So total left = u + 2u + 4u = 7u = 56 and thus u = 56/7 = 8.
Kaden gave away 8 - 2 = 6 marbles.
John gave away 6 / 2 * 9 = 27 marbles.
CHECK
Kaden Adam John
Gave 6 12 27 (6:12:27 = 2:4:9)
Left 8=2+6 16 32 (sum = 56)