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Question
Answer
waterflow
y= 16/(x+2)2
dy/dx = -2(16)/(x+2)3
= -32/(x+2)3
dy/dx = dy/dt* dt/dx = 0.25/-0.05 = -5
-5 = 32/(x+2)3
x= (32/5)1/3 -2 = 2(4/5)1/3 -2
When x= 2(4/5)1/3 -2,
y = 4(4/5)-2/3
Note: your written working dy/dx on the question is wrong as the order of differentiation in the numerator is reverse. Also note the minus sign for dx/dt for decreasing x.
Pls refer to https://www.mathcentre.ac.uk/resources/uploaded/mc-ty-quotient-2009-1.pdf
there must be a minus sign for this question for the dy/dx, you have reverse the order in the numerator resulting in no minus sign.