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1/4 + 1/16 + 1/64 + ….. is a geometric progression with a = 1/4= first term.

r = 1/4

and n = ∞

Given Sn = a(1 – rn ) / ( 1- r) ,

For the above series , when n = ∞,

(1/4) = 0

So Sn = 1/4 ( 1 – 0 ) / ( 1- 1/4) = (1/4 )* (4/3) = 1/3

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Good solution!  The question is supposed to be for P5 students.  Don’t know how on earth P5 kids are supposed to know AP/GP.

1 Reply 1 Like

Think this question is for Primary school Olympiad, so perhaps GP is one of the topics that these gifted students must know. 

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