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Question

Answer

(a) At point C,  y = k/3 and

at point A , y = 2k

AC = 2k – k/3 = 5k/3 (proved)

(b) Since ABCD is a parallelogram, at point B, it is equidistant from A as point C from origin. 

At point B,

x = 2k

y = 2k + k/3 = 7k/3

So the coordinates of B is (2k, 7k/3)

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