AskQ logo

STUCK ON HOMEWORK?

ASK FOR HELP FROM OUR KIASUPARENTS.COM COMMUNITY!

Question

Answer

Yes!

0 Replies 2 Likes ✔Accepted Answer

(a) ∠DFG = ∠EDF = 32º      FG parallel to ED, alternate angles of parallelogram equals.

∠DFB = 45º  + 32º = 77º

∠FDB = 180º – 2 * 77º = 26º               Triangle FDB isosceles

(b) Since BC parallel to FD 

∠BCD = 180º- ∠CDF = 180º – 26º  – 35º = 119º

 

Note: your steps are correct, can simplify finding of ∠DFG .

0 Replies 1 Like