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∠PSR = 180º – 60º – 50º = 70º  Sum of interior angles is 180º  for triangle

∠PSQ = 180º – ∠PSR  = 110º         Straight angle for straight line is 180º 

∠SPQ  = 180º – 32º – ∠PSQ = 38º    Sum of interior angles is 180º  for triangle

Think all workings correct, not sure why marked wrong. 

Perhaps can be faster using the following method

∠PSQ = 60º  + 50º = 110º   Exterior angle of triangle is sum of two opposite interior angles

∠SPQ  = 180º – 32º – ∠PSQ = 38º    Sum of interior angles is 180º  for triangle

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