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(a)  ∠EFD  = 180º – 2*∠DEF = 180º – 2*53º = 74º       Triangle DEF is isosceles.

(b)  ∠ABC  = (180º – ∠BAC)/2 = (180º – 36º)/2 = 72º      Triangle ABC is isosceles.

(c) Since triangle WXZ is isoscles, and WY is perpendicular to XZ, so WY bisect ∠ZWX.

∠ZWY = ∠ZWX/2 = 86º/2 = 43º

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