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Q29) Area of △PQT = 1/2 x base x height
= 1/2 x PQ x QR
= 14cm2 (same area of △QRS, same height, same base)
Height of △PQT = QR = (14×2)/7 = 4cm

Q30) ∠EHI = 180° – 40° – 90° – 30° = 20° (sum of angles on straight line)
∠HFG = ∠EHF = 20° + 30° = 50° (alternate angle, EH parallel to FG)
∠HFG = ∠FHG (rhombus, sides same length)
∠FGH = 180° – 50° – 50°= 80° (sum of angles in triangle)

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