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A : B : C
4 : 9
      5 : 8
Since B has the same number of beads in both scenario, find common multiple of 9 and 5, which is 45.

A   : B   : C  :  T
20 : 45                  (x5)
        45 : 72           (x9)
20 : 45 : 72 : 137

855/45 = 19
137 x 19 = 2603
They have 2603 beads altogether.

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