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Question

Answer

10.

AC = 14cm

Total Area = 2 * 14 * 14 + 7 * 7 cm² = 441 cm²

Area of triangle CDF + Area of triangle BCK = 2* 1/2 * 7 *  14 cm²= 98 cm²

Area of shaded area = 441 – 98 cm² = 343 cm²

 

11.

∠ABC = 60º             equilateral triangle

∠ADB = ( 180 – 60º – 31º )/2 = 44.5º   triangle ADB isosceles

∠AEC = ∠BED = 180 – 44.5º – 31º = 104.5º

 

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