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PLEASE SUBMIT ONLY 1 QUESTION PER REQUEST SO THAT THINGS GET ARCHIVED EASILY.

1.

Assuming Devi has u stickers to begin with,
Calvin must haveĀ  u + 76 stickers at the beginning.

Now,

Calvin’s stickers after the exchange = 3 (Devi’s stickers after the exchange)

So,

(u/4) + (u + 76) = 3 (u – u/4)
(5/4)u + 76 = (9/4)u
u = 76

So, number of stickers Devi is left with = (3/4) 76 = 57 #

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