# Question

dinesh saved a total of 132 pieces of 50 cents, 20 cent and 5 cent in his piggy bank. He had 5 fewer 50 cent coins than 20 cent coins. The number of his 5 cent coin was 3 times the total number of 50 cent and 20 cent coins.

a) How many 20 cent coins did Dinesh have?

b) what was the total value of his 5 cent coins?

Let me try…

Suppose he has u 50-cent coins.

So he has u+5 20-cent coins.

And he has 3(u + u+5) 5-cent coins.

So in total,
u + (u+5) + 3(u+u+5) = 132
2u + 5 + 3(2u+5) = 132
2u + 5 + 6u + 15 = 132
8u + 20 = 132
8u = 112
u = 14

a) So he must he u + 5 = 14 + 5 = 19 20-cent coins #

b) Since he has 3(2u+5) = 3(2(14) + 5) = 99 5-cent coins,
The value in 5-cent coins he has is 99*0.05 = \$4.95 #

Got it!  Thanks.

0 Replies 1 Like
```Start by thinking of which coin he had the least of.
In this case, it is 50 cents. So supposed he had u of them.

50c : u
20c : u + 5
5c  : 3 x (u + u + 5) = 6u + 15

If drawing model, it will be something like:
50c:  U
20c:  U[5]
5c:  UUUUUU[15]

So total number of coins = 8u + 20 = 132. So u = 14.

a. Number of 20cents that he had: u + 5 = 14 + 5 = 19
b. Number of 5cents = 6u + 15 = 99.
Value of 5cents coin = \$4.95