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I can only solve this using simultaneous equations…

5C + 4T = 57.40 … (1)
1C + 5T = 14 … (2)

Multiplying (2) by 5:
5C + 25T = 70 … (3)

Subtracting (1) from (3):
21T = 12.60
T = $0.60 #

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