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In the end, let cheese be 1u and walnut be 2u

1u of cheese left is 3/4 of original, hence originally there are 4/3(u) of cheese.

2u of walnut is 2/7 of original, hence originally there are 7u of walnuts.

7u – 4/3(u) = 68

17/3(u) = 68

u = 12

Total baked= 7u + 4/3(u) = 25/3(u) = 100 ##

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