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Question

Answer

At first,

C -> 5u

T -> 3u

 

After,

C -> 4p = 5u – 486

C -> 28p = 35u – 3402

T -> 7p = 3u – 149

T -> 28p = 12u – 596

35u – 3402 = 12u – 596

23u = 2806

1u = 122

a) Total number of cookies at first -> 5u = 5 x 122

b) Answer: (3u – 149) – (5u – 486)

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