Hi ,

please se help on the above question .

Thanks very much !

Fly2High

Source: Catholic High

Hi ,

please se help on the above question .

Thanks very much !

Fly2High

Source: Catholic High

BigDevil

The 2 triangles shown above are equilateral triangles,

so each sector is 60 degrees.

Hence, the length of the arc is 1/6 of the circumference.

Since there are 6 of such arcs, the parameter formed

by the 6 arcs is equal to the circumference of one circle.

The total parameter of the shaded figure is

8r + circumference -> (8 x 15) + 2 x pi x 15 = 120 + 30pi

BigDevil

The 2 triangles shown above are equilateral triangles,

so each sector is 60 degrees.

Hence, the length of the arc is 1/6 of the circumference.

Since there are 6 of such arcs, the parameter formed

by the 6 arcs is equal to the circumference of one circle.

The total parameter of the shaded figure is

8r + circumference -> (8 x 15) + 2 x pi x 15 = 120 + 30pi

Fly2high

Thanks very much BigDevil !!

BigDevil

Welcome!