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A baker baked some cookies on Monday.  He sold 3/7 of them on Tuesday and 1/2 of the rest on Wednesday.

a. what faction of the cookies were left?

b. the baker baked another 732 cookies on Thursday and then he had twice as many cookies as he had on Monday.  How many cookies did he bake on Monday?

Source: Pei Chun Public

Answer

Hi,

This is a Remainder question.

We shall first list out the information. 

  Sold  sold  Left  Total 
Monday  3u   4u 7u
Tuesday    1 1 2
CR 6u 4u 4u 14u

So after Tuesday, he left with 4u out ofor 14u.

4/14 = 2/7

He baked another 732 cookies.

The last ratio become 1 : 2.

      14u / 1 = (4u + 732)/2

       28u = 4u + 732

      28u – 4u = 732

     24u = 732

    1u = 30.5

    14u = 14 × 30.5 = 427

 

 

 

 

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On Monday, he baked 7u cookies.

On Tuesday, he sold 3/7 x 7u = 3u cookies; left 4u cookies

On Wednesday, he sold 1/2 x 4u = 2u cookies; left 2u cookies

(a) He had 2u/7u = 2/7 of his cookies left

 

On Thursday, he baked another 732 cookies -> he had 2u + 732;

and had twice of what he had on Monday.

Twice of what he had -> 14u

14u = 2u + 732

12u = 732

1u = 61

On Monday, he baked 7u -> 7 x 61 = 427 cookies

 

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thanks BigDevil

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You are welcome. 🙂

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