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These formulas bring back the old school day memories …..

You’re helpful ! guys.

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Thank you, Ender. Very useful link.

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Lol.  We found the same article 🙂

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post-19090-1

Here’s a good article that explains how to use the law of cosines to find angles in a triangle when all 3 sides are given.

The largest angle C will be the angle formed from the 2 sides a=4u and b=5u.  The longest side c=8u will form the base of the triangle.

Hence, cos (C) = (a2 + b2 – c2) / 2ab = (42 + 52 – 82) / 2(4)(5) = -0.575

Hence C = cos-1(-0.575) = 125.1o

#Corrected 9 Oct.

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post-19090-1

Here’s a good article that explains how to use the law of cosines to find angles in a triangle when all 3 sides are given.

The largest angle C will be the angle formed from the 2 sides a=4u and b=5u.  The longest side c=8u will form the base of the triangle.

Hence, cos (C) = (a2 + b2 – c2) / 2ab = (42 + 52 – 82) / 2(4)(5) = -0.575

Hence C = cos-1(-0.575) = 125.1o

#Corrected 9 Oct.

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Thanks, Chief. You have been a great help. But I believe you made a computational error. Should be -0.575

🙂

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You are right! Next time I need to use a proper calculator instead of the one in Windows.

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