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Question

Hi,

Anyone can hep to answer this question? TIA.

Sammy has 40 marbles.  He has 10% more marbles than John.  How many marbles did both boys have?

Answer

If sammy had 10% more than John, he would have 110 units and John would have 100 units. 

Amount John would have will be (40/110) x 100 =36.3 (3s.f)

This would not be right as the number of sweets should be an integer

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Sammy has 40 marbles.  He has 10% more marbles than John.  How many marbles did both boys have?

76 (assuming 9 units John and 10 units Sammy: this is the only reasonable interpretation as the qn is not phrased well)

 

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Sammy — 100%

John — 100% – 10% = 90%

100% + 90% = 190%

 

100% –> 40

190% –> 40 x 190/100 = 76

 

They had 76 marbles.

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Hi Kelvinho,

I think your interpretation on this statement is not correct. 

Sammy has 10% more than John.

Then John should be 100%, Sammy should be 110%.

This is a question error.

It should be John has 10% less than Sammy. 

When we use more than or less than someone, that someone is 100%.

 

 

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Sammy has 40 marbles.  He has 10% more marbles than John.  How many marbles did both boys have?

110% ——- 40
1% ——- 40/110 = 4/11
110% + 100% = 210% ——- 4/11 x 210 = 76 4/11

Ans : 76 4/11 marbles.
Note : Question is flawed due to 4/11 marble.

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Something wrong with the question.

If John has 36 marbles, and Sammy has 10% more, 

36 x 1.1 = 39.6

You can never get an even 40 marbles.

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This is question error.

It should be John has 10% less than Sammy.

When we use more than or less than  someone, that someone is 100%.

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As what BigDevil mentioned. Could there be something wrong with the question ? or probably some typo errors.

Based on the info,

John = 40 x 100/110 = 36.36 marbles.

Seems like the answer will not be a “whole number” ???

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I also interpret “He has 10% more marbles than John”, as John being the 100%, and Sammy is the 110%.

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