# Question

There were 30 more 20 cents coins than \$1 coins in a box. the difference in value between all the \$1 coins and all the 20 cents coins is \$90. express the number of \$1 coins as a fraction of the number of 20 cent coins. give your answer in the simple form.

\$0.20 x 30 = \$6

\$90 – \$6 = \$84

\$1 – \$0.20 = \$0.80

\$84 / \$0.80 = 105

105 + 30 = 135

105/135 = 7 : 9

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There were 30 more 20 cents coins than \$1 coins in a box. the difference in value between all the \$1 coins and all the 20 cents coins is \$90. express the number of \$1 coins as a fraction of the number of 20 cent coins. give your answer in the simple form.

0.2 (number of \$1 coins + 30) +90 = number of \$1 coin

0.2 number of \$1 coins + 96 = number of \$1 coin

Number of \$1coins = 120

Number of 0.2 coints = 150

Fraction = 4/5

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This is a Quantity Amount question.

 20cent \$1 Total Quantity 1u + 30 1u Each 0.2 1 Product 0.2u + 6 1u

0.2u + 6 +90 = 1u           (amount of \$1 more than 20 cent)

96 = 1u – 0.2u

0.8u = 96

1u = 96 ÷ 0.8 = 120

120 + 30 = 150

120 / 150 = 4/5

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Let no. of \$1 coins = u

30 more 20 cent coins → 30 x \$0.2 = \$6

Value of \$1 coins → \$u

Value of 20 cent coins → \$0.2u + \$6

Difference in value → \$u – \$0.2u – \$6

\$4/5u = \$90 + \$6

4/5u = 96

u = 120

No. of \$1 coins / No. of 20 cent coins → 120/150 → 4/5

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