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Question

Hi I would appreciate it if I could get help with this question…

Gordon gave 1/3 of his sweets to Conrad. After that, Conrad gave Gordan 1/4 of what he had. In the end, Gordon had 64 sweets and Conrad had 72 sweets. How many sweets did Gordan have at first?

Thank you:)

 

Answer

Work backwards. Total sweets is unchanged (not used this concept, but can be a constant check)

  Gordon Conrad Total
Final 64 72 (=3/4) 136
 Conrad takes back his 1/4 64-24 96 (=4/4) 136
  40 (=2/3) 96 136
 Gordon takes back his 1/3 60 (=3/3) 96-20 136
Original 60 76# 136
checking:      
Gordon gives 1/3 60-20=40 76+20=96  136
Conrad gives 1/4 40+24=64 96-24=72 136
       

 

0 Replies 2 Likes ✔Accepted Answer

This is a After Before question. 

  Gordon  Conrad   Total
After   64 72 (3u)  
Before   40  (2u)  96 (4u)  
Before  60 (3u) 76  

73 ÷ 3 × 4 = 96

64 – 24 = 40

40 ÷ 2 × 3 = 60

96 – 20 = 76

 

0 Replies 1 Like

This is a After Before question. 

  Gordon  Conrad   Total
After   64 72 (3u)  
Before   40  (2u)  96 (4u)  
Before  60 (3u) 76  

73 ÷ 3 × 4 = 96

64 – 24 = 40

40 ÷ 2 × 3 = 60

96 – 20 = 76

 

0 Replies 1 Like
post-20000

Step 1: work backwards. Draw the model for 72 and 64.

step 2: since Conrad gave Gordon 1/4 he would have 3/4 left. So 3 units = 72 

and 1 unit is 24. 

Step 3: see red transfer. Gordon’s one unit of 24 has to be given back to Conrad.

step 4: since Conrad gave Gordon 1/3 of what he has, then he would have 2 units left .

2 units = 64-24 = 40.

so 1 unit = 20 

and 3 units = 60.

gordan would have 72 + 4 = 76.

0 Replies 1 Like