# Question

Julie’s father gave her some money to buy some crackers. at first, she bought cracker of 2 different sizes, 7 large and 3 small for \$30.20.

she could not buy another large packet of cracker as she was short of \$0.90. instead she bought another small packet of fish crackers and had \$1.70 left. how much money did Julie’s father give her?

Key understanding is one small packet is \$2.60 cheaper (\$1.70 money left + \$0.90 shortage) than one large packet.

7 Large + 3 Small = \$30.20 (10 packets)

Replacing to all 10 Small packets = \$30.20 – \$2.60×7 (\$ saved by buying 7 smaller packets instead of 7 large packets)

1 Small pack = \$12/10 = \$1.20

Total money = \$30.20 + 1 additional small packet + \$1.70 leftover

= 30.20 + 1.20 + 1.70 = \$33.10#

one small = u

one large = u+2.60

7 large + 3 small = 30.20

7(u+2.60) + 3u = 30.20 –> u=1.20

Total money = 30.20 + u + 1.70 = \$33.10#

L = S+2.60

7L + 3S = 30.20

7S + 7×2.60 + 3S = 30.20

10S = 12

S=1.20

Total money = 30.20 + S + 1.70 = \$33.10#

0 Replies 1 Like ✔Accepted Answer

1 small packet = 1u

1 large packet = 1u + 1.70 + 0.90 = 1u + 2.60

3 small = 3u

7 large = 7u + \$18.20

total cost will be 10u + 18.20 = 30.20

10u = \$12

1u = \$1.20

30.20 + 1.20 + 1.70 = \$33.10

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Julie’s father gave her some money to buy some crackers. at first, she bought cracker of 2 different sizes, 7 large and 3 small for \$30.20.

she could not buy another large packet of cracker as she was short of \$0.90. instead she bought another small packet of fish crackers and had \$1.70 left. how much money did Julie’s father give her?

7 Large + 3 Small = 30.20

1 Small = Remainder – \$1.70

1 Large = Remainder + \$0.90

7 (Remainder + \$0.90) + 3 (Remainder – \$1.70) = \$30.20

7 Remainder + \$6.30 + 3 Remainder – \$5.10 = \$30.20

10 Remainder + \$1.20 = \$30.20

10 Remainder = 29

Remainder = \$2.90

Amount = \$2.90 + 30.20 = \$33.10

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