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Question

Dear kind parents,

Please advise the solution to this question.

Many thanks in advance!

Gordon gave 1/3 of his sweets to Conrad. After that, Conrad gave Gordon 1/4 of what he had. In the end, Gordon had 64 sweets and Conrad had 72 sweets. How many sweets did Gordon have at first?

 

Source: Anglo-Chinese School Junior

Answer

Work backward

In the end,
G -> 64
C -> 72

Conrad’s 72 is what’s left after he gave Gordon 1/4 of what he had.
So 72 is 3/4 of what Conrad had.
Before giving Gordon 1/4, Conrad had 72 x 4/3 = 96
Gordon had 64 – (96 – 72) = 40

Gordon’s 40 is what’s left after he gave Conrad 1/3 of what he had.
So 40 is 2/3 of what Gordon had.
Before giving Conrad 1/3, Gordon had 40 x 3/2 = 60
Conrad had 96 – (60 – 40) = 76

In the beginning,
Gordon had 60
Conrad had 76

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Hello there was a similar question posted.  U might want to scroll back.

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