 # Question

Mrs Tan ordered 82 ice creams to be shared equally by 41 students in her class. All the boys were present but some girls were absent. After giving each student who was in class one extra ice cream each, Mrs Tan still had 1 ice cream left.

a) how many girls were absent?

b) There were twice as many boys as girls who were in her class.

what was the total number of girls in Mrs Tan’s class?

Would need some guide as teacher never marked the question

4 Answers

# Answer

Initial plan ……

82 ice cream shared by 41 students  —>  Each student  =  82 / 41  =  2 ice-cream

But some girls absent .….

Each student received 1 extra ice cream  —> Each student  =  2 + 1  =  3 ice cream

and 82 / 3 =  27  1/3   ( or  27 R1  )

—> There are 27 students ( each 3 ice cream ) present with 1 extra ice cream left over.

(a) Number of girls absent  =  41 – 27  =  14

Out of these 27 students present, there were twice as many boys as girls

—> Number of girls present = 27 /3 = 9

—> Number of boys present = 27 – 9 = 18

(b) Total number of girls in the class  =  9 + 14  =  23

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Good suggestion …. while evaluating “82 / 3”, the student will probably have to go through the process of using long division to acknowledge a quotient “27” and a remainder “1”.  I suppose thereafter, they can have the option to present the answer as 27 R1 or as a mixed number fraction 27 1/3.

As mixed number fraction is only being introduced in early semester of P4 while long division with remainder is already being taught in P3 level, hence if the student is not able to interpret mixed number fraction well, then I would suggest they should write 82 / 3 = 27 R1.

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a) 82 – 1 = 81

81 / 3 = 27

41 – 27 = 14

b) 27 / 3 = 9

9 + 14 = 23

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Mrs Tan ordered 82 ice creams to be shared equally by 41 students in her class. All the boys were present but some girls were absent. After giving each student who was in class one extra ice cream each, Mrs Tan still had 1 ice cream left.

a) how many girls were absent?

b) There were twice as many boys as girls who were in her class.

what was the total number of girls in Mrs Tan’s class?

Total Pupils Remaining = 1 Unit

3Units = 81 (82 – 1)

1 Unit = 27

41 – 27 = 14 girls were absent (0 boys absent)

Boys = 2 Times Girls

27 * 1/3 = 9 (9 girls in class remaining)

Total Girls = 9 + 14 = 23

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