AskQ logo

STUCK ON HOMEWORK?

ASK FOR HELP FROM OUR KIASUPARENTS.COM COMMUNITY!

Question

Lamp posts are positioned at intervals of 120 m along a road and pots of bougainvillea plants placed at intervals of 96 m. The first pot of bougainvillea plant is placed at the foot of the first lamp post.

 

a) If the last pot of bougainvillea plant is placed at the foot of a lamp post, find the distance between the first and the last pot of plant.

b) Find the total number of lamp posts and pots of bougainvillea plants within this road segment.

 

** Need help with b). Thank you in advance.

Answer

a)

120=5x3x22

96=3×25

LCM=5x3x25

         =480

b)

No. of lamp posts in this segment= 480÷120+1

                                                             = 5

No. of  pots of bougainvillea plants= 480÷96+1

                                                               =6

Total number of lamp posts and pots of bougainvillea plants= 5+6

                                                                                                              =11

0 Replies 1 Like

a) To find lowest common multiple of 120 and 96

Taking multiples of 120 – 120, 240, 360, 480 and so forth, try dividing by 96.

480 is the lowest multiple of 120 that is divisible by 96. Thus the answer is 480m.

 

b) Total number of lampost = (480/120)+1 = 5

    n/b: add one for the first lampost.

    LP1 —-120m—-LP2 —-120m—-LP3 —-120m—-LP4 —-120m—-LP5

    Total number of bougainvillea plant pot = (480/96)+1 = 6

     n/b: add one for the first pot.

     Pot1 –96m–Pot2 –96m–Pot3 –96m–Pot4 –96m–Pot5 –96m–Pot6

Total number of lamp posts and pots of bougainvillea plant = 5+6 = 11

0 Replies 1 Like

a) Find the lowest common multiple between 96 and 120. Answer will be 480.

b) Take 480 divide by 96 = 5.

take 480 divide by 120 = 4.

5+4+2= 11

0 Replies 1 Like

120  240  360  480 –> 5 lamp posts

96  192  288  384  480 –> 6 pots of plant

5 + 6 = 11 (Ans)

 

0 Replies 2 Likes