# Question

Column A Column B Column C Column D
Row 1                 2                 3                 4                5
Row 2                9                 8                 7                 6
Row 3               10                11               12                13
Row 4               17                16               15                14
…… … … … …

In which column will the number 234 appear?

pls help to explain how to solve this kind of Questions?

For this kind of question, you want to find the remainder after you divide the number in the boxes by the…”frequency”?

So for the question above, the arrangement pattern is

A – B – C – D – (repeat) – A – B – C – D

This has a frequency of 4, ie, the pattern repeats after every 4 numbers.

So you divide the numbers in the boxes by 4, and you will realise that under column A, the remainders are always 0, always 1 under B, always 2 under C, and always 3 under D.

 A B C D 6 / 4 -> 1R2 7/4 -> 1R3 8/4 -> 2R0 9/4 -> 2R1 10/4 -> 2R2 11/4 -> 2R3 12/4 -> 3R0 13/4 -> 3R1 14/4 -> 3R2 15/4 -> 3R3

Therefore, 134 / 4 -> 33 R 2 can be found in column C.

Likewise for your second question, the pattern is

A – B – C – D – D – C – B – A – (repeat) – A – B – C – D – D – C – B – A

This has a frequency of 8, so you find the remainder by dividing by 8.

 A B C D 2/8 -> 0R2 3/8 -> 0R3 4/8 -> 0R4 5/8 -> 0R5 9/8 -> 1R1 8/8 -> 1R0 7/8 -> 0R7 6/8 -> 0R6 10/8 -> 1R2 11/8 -> 1R3 12/8 -> 1R4 13/8 -> 1R5

The number 234 when divided by 8 has a remainder of 2, so it will be in column A.

Big Devil. thank you so much for all the detail explanation. i am fully aware how to handle this kind of Qs now.

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Method 1 :
134/4 = 33R2
R2 ——- (start counting from 1 in column B)

Method 2:
134 – 6 = 128
128/4 = 32R0
R0 ——- (start counting from 6 in column B)

Ans : (3) Column C.

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