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Question

Please help with this question, m.thanks in advance

Gordon had two crates containing both lemons and pears in each crate.

The ration of the number of lemons to that of pears in Crate A was 7:5.

The ration of the number of lemons to that of pears in Crate B was 3:1.

There was an equal number of fruits in each crate.

Gordon transferred 1/5 of the pears from Crate A to B.

He then threw away 84 lemons from Crate B.

The ration of the number of pears to that of lemons in Crate B then became 5:6.

What was the total number of fruits in both crates at first?

Answer

1 Reply 1 Like ✔Accepted Answer

Thank you Siglapmath

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Before transfer —
Crate A
lemons : pears : total
7u : 5u : 12u

Crate B
lemons : pears : total
3 : 1 : 4
9u : 3u : 12u

After transfer —
Crate A —
lemons pears : total
7u : 4u : 11u

Crate B —
lemons : pears
(9u – 84) : 4u

4u x 6 = 24u ——- (9u – 84) x 5 = 45u – 420
45u – 24u = 21u ——- 420
1u ——- 420/21 = 20
12u + 12u = 24u ——- 24 x 20 = 480

Ans : 480 fruits.

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Hi zinmkw

Could you check if the last ratio should be 6:5 instead?

 

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Hi Siglapmath 

Its not 6:5, thanks.

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1 Reply 1 Like ✔Accepted Answer

Thank you Siglapmath

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  Lemon Pear Total
Crate A 7u 5u 12u
Crate B 9u 3u 12u
       
A – 1/5 pears -> B (1u)      
B – threw 84 lemons      
Crate B (in the end) 9u – 84 4u  

In the end, Lemon(B) : Pear(B) -> 6:5

6p = 9u – 84

30p = 45u – 420

5p = 4u

30p = 24u

45u – 420 = 24u

21u = 420

u = 20

Total number of fruits at first -> 24u = 480

1 Reply 1 Like

Thanks again BigDevil 

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1 Reply 2 Likes

Thanks a lot, it’s easy to understand. Appreciate your explanation Acestarling. 

1 Reply 1 Like

Glad that it helps you.

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