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Answer
alfretztay
chocolates : sweets : total
2u : 7u : 9u
299.60 – 92.40 = 207.20
207.20/2 = 103.60 (total cost of sweets)
103.60/2 = 51.80 (1u of sweets)
103.60 + 92.40 = 196 (total cost of chocolates)
197/7 = 28 (1u of chocolates)
(51.80 – 28)/1.70 = 14 (number of chocolates in 1u)
14 x 9 = 126
Ans : 126 chocolates and sweets.
theoryoflearning
In the last line, change “bags” to “total candy bought”
Not sure if Primary students these days are expected to learn to solve simultaneous equations, this question is really pretty tough.
SAHMom
Hi. P6 are not really required to know how to solve simultaneous equations. They learn heuristics methods for solving in their less complex world, like in my picture. This type of questions have always popped out here once in a while. You can run through the solutions on this platform for examples of other heuristics tools in use.
Total Chocs. Sweets
Ratio 2sets 7sets
Cost $299.60 ($299.6-$92.4)/2=$103.60 $196
cost per set $103.6/2=$51.80 $196/7=$28
no. of chocs per set = big diff/small diff=($51.8-$28)/1.7=14
total sweets and chocs =(2+7) sets x 14 = 126#
sorry alignment abit out
SAHMom
Hi. P6 are not really required to know how to solve simultaneous equations. They learn heuristics methods for solving in their less complex world, like in my picture. This type of questions have always popped out here once in a while. You can run through the solutions on this platform for examples of other heuristics tools in use.
Total Chocs. Sweets
Ratio 2sets 7sets
Cost $299.60 ($299.6-$92.4)/2=$103.60 $196
cost per set $103.6/2=$51.80 $196/7=$28
no. of chocs per set = big diff/small diff=($51.8-$28)/1.7=14
total sweets and chocs =(2+7) sets x 14 = 126#
sorry alignment abit out
BigDevil
Amount paid for chocolate = (299.60 – 92.40) / 2 = $103.60
Amount paid for sweets = $103.60 + $92.40 = $196
| Cost | Total | Amount paid | ||
| Chocolate | 2u | S + 1.70 | 2u × (S + 1.70) = 2uS + 3.4u | $103.60 |
| Sweets | 7u | S | 7u × S = 7uS | $196 |
7uS = 196
uS = 196 ÷ 7 = 28
2uS + 3.4u = 103.6
(2 × 28) + 3.4u = 103.6
3.4u = 103.6 – 56
u = 47.6 ÷ 3.4 = 14
Total number of chocolate & sweets -> 9u = 126