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Before :
red ——- 7u
yellow ——- 7u
blue ——- 5p

7u + 7u + 5p = 14u + 5p ——- 3624
2u + 2p ——- 3624 – 3024 = 600
14u + 14p ——-4200
14p – 5p = 9p ——- 4200 – 3624 = 576
1p ——- 576/9 = 64
5p ——- 64 x 5 = 320

or

After :
red ——- 7u
yellow ——- 7u – 2u = 5u
blue ——- 5p – 2p = 3p

7u + 5u + 3p = 12u + 3p ——- 3024
2u + 2p ——- 3624 – 3024 = 600
12u + 12p ——- 3600
12p – 3p = 9p ——- 3600 – 3024 = 576
1p ——- 576/9 = 64
5p ——- 64 x 5 = 320

Ans : 320 blue sweets.

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Most important step is to summarise given info (in black font in table) first.

  Red Yellow Blue Total
At first

same

(#3a. 7u)

same   

(#1b. 7u)

            

(#2b. 5p) =3624-14u

3624
 Change  

 less ?  

(#1c. 2u)

less ??

(#2c. 2p)

 
 End

 

(#3b. 7u)  

5/7        

(#1a. 5u)

3/5      

(#2a. 3p) =3024-12u

3024
Follow steps#                        Equate for 15p  

Method 1: Solving simultaneous equations (quite complex for P6, not recommended)

7u + 7u + 5p = 3624

7u + 5u + 3p = 3024                                 —-> 3u+3p  + 9u = 3024

         2u+2p = 600  —> 1u+1p=300                                                             —> p=64, 5p=320# (blue) 

                                —> 3u+3p=900,  from above: 900 + 9u=3024      —>  u =236

Method 2: Equate for 15p in column “BLUE” (I think it is easier for P6):

3(3624-14u) = 5(3024-12u)

60u-42u  = 5×3024 – 3×3624   –> u= 236

put into intial Blue: 5p= 3624-14u = 320#

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