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Question

Answer

Before

Hendon → u

Alvin → 117 – u

After

Hendon bought 8 → u + 8

Alvin gave 20 → 117 – u – 20 = 97 – u

 

Given: Hendon has 2 times as many as Alvin

u + 8 = 2 × (97 – u)

u + 8 = 194 – 2u

3u = 186

u = 62

At first, Alvin had (117 – u) = 117 – 62 = 55

1 Reply 2 Likes ✔Accepted Answer

Check

Before

Hendon → u = 62

Alvin → 117 – u = 55

After

Hendon bought 8 → 62 + 8 = 70

Alvin gave 20 → 55 – 20 = 35

70 is 2 times of 35. 

Checked

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After :

Hendon ——- 2u

Alvin ——- 1u

Before :

Hendon ——- 2u – 8

Alvin ——- 1u + 20

2u – 8 + 1u + 20 = 3u + 12 ——- 117

1u ——- (117 – 12)/3 = 35

35 + 20 = 55

Ans : 55 marbles.

 

1 Reply 1 Like

Thank you..:)

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 You are most welcome. 🙂

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