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Question

Jack has a total of 60 chocolate and sweets for sale. after selling 1/3 of the chocolates and 2/3 of the sweets, he had twice as many sweets left as chocolate. how many sweets did Jake sell?

Answer

chocolate : 1u + 1u + 1u = 3u
sweets : 4u + 4u + 4u = 12u
 
3u + 12u = 15u ——- 60
1u ——- 60/15 = 4
(2/3) x 12u = 8u ——- 8 x 4 = 32
 
Ans : 32 sweets.
0 Replies 0 Likes ✔Accepted Answer

Chocolates -> 3u

Sweets -> (60 – 3u)

¹⁄3 of chocolates sold, left -> 23 × 3u = 2u

23 of sweets sold, left -> 13 × (60 – 3u) = (20 – u)

Given: sweets left was twice of chocolates left

(2o – u) = 2 × 2u

5u = 20

u = 4

Chocolates -> 3u = 12

Sweets -> 60 – 12 = 48

Number of sweets sold -> 23 × 48 = 32

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