Find Tuition/Enrichment Centres

AskQ logo

STUCK ON HOMEWORK?

ASK FOR HELP FROM OUR KIASUPARENTS.COM COMMUNITY!

Question

Answer

if 45 boys left,the ratio would be 5:3(in boys is to girls)

So, we can rewrite it as (5p+45):3p

if 38 girls left,the ration would be 2:1

So,we can rewrite it as 2u:1u+38

From here, we can know that 2u=5p+45 and 1u+38=3p

Then,2u-45=5p and 1u+38=3p

after that,6u-135=15p and 5u+190=15p

then,6u-135=5u+190

Finally,6u-5u=190+135

which means 1u=325

girls=325+38=363

boys=325×2=650

total number of children:650+363=1013

0 Replies 0 Likes

if 45 boys left,the ratio would be 5:3(in boys is to girls)

So, we can rewrite it as (5p+45):3p

if 38 girls left,the ration would be 2:1

So,we can rewrite it as 2u:1u+38

From here, we can know that 2u=5p+45 and 1u+38=3p

Then,2u-45=5p and 1u+38=3p

after that,6u-135=15p and 5u+190=15p

then,6u-135=5u+190

Finally,6u-5u=190+135

which means 1u=325

girls=325+38=363

boys=325×2=650

total number of children:650+363=1013

0 Replies 0 Likes

Method 1 :
(number of boys – 45)/number of girls = 5/3
3 x number of boys – 135 ——- 5 x number of girls
3 x number of boys ——- 5 x number of girls + 135
number of boys/number of girls – 38) = 2/1
1 x number of boys ——- 2 x number of girls – 76
3 x number of boys ——- 6 x number of girls – 228
6 x number of girls – 228 ——- 5 x number of girls + 135
number of girls ——- 135 + 228 = 363
number of boys ——- 2 x 363 – 76 = 650
650 + 363 = 1013

Method 2 :
Scenario 1 : If 45 boys left the party,
boys : girls
5u : 3u

Scenario 2 : If 38 girls left the party,
boys : girls
2p : 1p

5u + 45 ——- 2p
3u ——- 1p + 38
5u + 45 ——- (3u – 38) x 2 = 6u – 76
6u – 5u = 1u ——- 45 + 76 = 121
8u ——- 8 x 121 = 968
968 + 45 = 1013

Ans : 1013 children.

0 Replies 0 Likes
Find Tuition/Enrichment Centres