# Question

Mrs Tan packed a total of 1078 calculators and board games into 49 boxes. The calculators and board games were packed in separate boxes. Each box could hold either 28 calculators or 7 board games only.

How many board games were there in all?

Source: Rosyth

3 Answers

# Answer

No. of boxes for calculators  = U

No. of boxes for games = 49 – U

(28 x U) + 7x (49 – U) = 1078

=> 21U = 1078 – 343

U = 35

No. Of boxes of games = 49 – 35 =14

No. Of board games = 14 x 7 = 98

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Thank you Nebbermind…….this is interesting. Didn’t know can use algebra method.

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Use Assumption method.

Assume all 49 boxes contained board games.

49 × 7 = 343

Short of :  1078 – 343 = 735 to be made up by calculators

28 – 7 = 21

735 ÷ 21 = 35 (boxes with calculators)

Number of boxes of board games -> 49 – 35 = 14

Number of board games -> 14 × 7 = 98

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Thank you BigDevil. Didn’t know can use assumption method. Got it!

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You are welcome!

You can always rephrase the question into the more familiar…

49 animals on a farm with a total of 1078 legs.

Animal A has 7 legs, while Animal B has 28 legs.

How many legs belong to Animal A are there?  😛

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Ah! Nice!

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49 x 7 = 343 (assuming all 49 boxes are each packed with 7 board games)
1078 – 343 = 735
28 – 7 = 21 (difference)
735/21 = 35 (boxes packed with calculators)
(49 – 35) x 7 = 98

Ans : 98 board games.

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Thank you alfretztay. Didn’t know can use assumption method.

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You are welcome, laughingcat. 🙂

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