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# Question

# Answer

Suggested answer:

Side of square = 16cm

Area of smaller quadrant = 1/4 x 8 x 8 x pi = (16 pi )cm^{2}

Area of triangle B = 1/2 x 8 x 8 = 32 cm^{2}

Area of A => 16 pi cm^{2} – 32 cm^{2 }

Area of shaded + A = 1/8 of bigger circle

1/8 x 16 x 16 x pi = 32 pi

Shaded area + (16 pi – 32) cm^{2} = (32 pi) cm^{2}

Area of Shaded area will be

(32 pi – 16 pi + 32 ) cm^{2}

= (16 pi + 32) cm^{2}

=** 82.27 cm ^{2}**

Suggested answer:

Side of square = 16cm

Area of smaller quadrant = 1/4 x 8 x 8 x pi = (16 pi )cm^{2}

Area of triangle B = 1/2 x 8 x 8 = 32 cm^{2}

Area of A => 16 pi cm^{2} – 32 cm^{2 }

Area of shaded + A = 1/8 of bigger circle

1/8 x 16 x 16 x pi = 32 pi

Shaded area + (16 pi – 32) cm^{2} = (32 pi) cm^{2}

Area of Shaded area will be

(32 pi – 16 pi + 32 ) cm^{2}

= (16 pi + 32) cm^{2}

=** 82.27 cm ^{2}**

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