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P5 Mathematics

Question post on Thu, 28/09/2017 9:18pm

Pls help to solve this question. Tks.

BigDevil · Answer 1 · Post on Thu, 28/09/2017 9:52pm

∠ABD = ∠BDC = 62º (alternate angles)

∠BAD = ∠ABD = 62º (isosceles ΔABD)

∠ADB = 180º – 62º – 62º = 56º

BigDevil · Answer 2 · Post on Thu, 28/09/2017 9:52pm

∠ABD = ∠BDC = 62º (alternate angles)

∠BAD = ∠ABD = 62º (isosceles ΔABD)

∠ADB = 180º – 62º – 62º = 56º

alfretztay · Answer 3 · Post on Thu, 28/09/2017 9:51pm

angle ABD = angle BDC = 62 (alternate angles)
angle ADB = 180 – 62 x 2 = 56

Ans : 56 degrees.