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Question

On the school’s first fund-raising campaign, Class A raised 4 times as much money as Class B. On the second fund-raising campaign, Class A raised another $480 while Class B raised another $320. Class A raised 3 times as much money as Class B at the end of the two campaigns. What was the total amount of money raised by the two classes at the end of two campaigns ?

Source: Pei Hwa Presbyterian Primary

Answer

                 Class A            Class B

At first        4u                      u

            +480 |                       | +320

In the end    3p                    p

4u = 3p  – 480 

u = p – 320

4u = 4(p –  320) 

      = 4p –  1280

4p – 1280 = 3p – 480

4p-3p = 1280-480

 p = 800

4p = 4 × 800

     = 3200

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4u + 480 ——- 3p
1u + 320 ——- 1p
4u + 1280 ——- 4p
1p ——- 800
3p + 1p = 4p ——- 3200

Ans : $3200.

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Class A

Class B

1st campaign

4 units

1 unit

2nd campaign

+ $480

+ $320

In the end

4 units + $480

(3 units)

1 unit + $320

(1 unit)

 

 

To make the amount collected by Class B the same as Class A, we do the following step:

(1 unit + $320) x 3 = 3 units + $960

4 units + $480 = 3 units + $960

4 units – 3 units = $960 – $480

1 unit = $480

 

Amount collected by each class in the end

(Class A)

4 units + $480

= (4 x $480) + $480

= $1920 + $480

= $2400

(Class B)

1 unit + $320

= $480 + $320

= $800

 

Total amount of money raised = $2400 + $800

                                                           = $3200 (Ans)

 

 

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