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Question

Joyce and kaylene had some stickers.The number of stickers joyce had was 4/5 of what kaylene had.joyce then gave 5/8 of her stickers to kaylene.As a result ,kaylene had 108 more stickers than joyce.how many stickers did joyce have atfirst?

Answer

                   J  :  K

At first      4  :  5

   ×2           8  :   10

      -5u       |        |+5u

Then          3  :   15

? K more than J = 15u-3u

                              = 12u

12u = 108

1u = 108/12

      9

? J at first = 8u

                   = 8×9

                   = 72 ( ans)

1 Reply 0 Likes ✔Accepted Answer

Thank you so much conceptual maths

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