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Question

3 children are comparing their masses. Albert is 60 kg heavier than Collin and Bob is 8 kg heavier than Collin. If the total mass of Albert and Bob is 3 times the total mass of Bob and Collin, find Bob’s mass.

Answer

A -> C + 60

B -> C + 8

A + B -> 3(B + C)

2C + 68 -> 3B + 3C

2C + 68 -> 3(C + 8) + 3C

2C + 68 = 3C + 24 + 3C

6C – 2C = 68 – 24

4C = 44

C = 44 ÷ 4

    = 11

B -> (11 + 8) kg

    = 19 kg (ans)

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Albert ——- Collin + 60
Bob ——- Collin + 8
Albert + Bob ——- 3 x Bob + 3 x Collin
Albert ——- 2 x Bob + 3 x Collin
Collin + 60 ——- 2 x Collin + 16 + 3 x Collin
Collin ——- (60 – 16)/(5 – 1) = 11
Bob ——- 11 + 8 = 19

Ans : 19 kg.

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