Question: Find the smallest number that should be added to 1628 so that the sum is exactly divisible by 4, 5 and 6.

Please anyone help me with this question.

Question: Find the smallest number that should be added to 1628 so that the sum is exactly divisible by 4, 5 and 6.

Please anyone help me with this question.

SAHMom

# alfretztay Post on Sun, 21/01/2018 10:05pm

4 x 5 x 6 = 120

1628/120 = 13R68

120 – 68 = 52

Ans : 52.

Hi Alfretztay, using multiples of 120 may not work in below example.

Suppose the question says addition to 1618

4 x 5 x 6 = 120

1618/120 = 13R58

120 – 58 = 62

Ans : 62. (Not acceptable as it means 1680 is the next number but in actual fact, 1620 is the next number and the smallest number to add is 2)

If using LCM =60

1618/60 = 26.96 (times)

Next number is 27 times 60 = 1620

Difference to add = 1620 – 1618 = 2#

alfretztay

4 x 5 x 6 = 120

1628/120 = 13R68

120 – 68 = 52

Ans : 52.

SAHMom

LCM of 4, 5, and 6 = 2 x 2 x 5 x 3 = 60

The number to be divided by 4, 5 and 6 must be a multiple of 60.

1628 / 60 = 27.13

Next number is 28 x 60 = 1680

Smallest number to add = 1680 – 1628 = 52#