David had 3/17 of the total amount of money he and Faizal had. After David’s father gave him $76, he had 2/3 as much money as Faizal. How much money did David have now?

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# Question

# Answer

Hi Logan77!

To solve this, you have to make the denominators the same.

First, we find Faizal’s amount in fractions:

1-3/17 = 14/17

We know 14/17 is equal to 3/3 for Faizal’s case, since his amount did not change.

Hence, through cross-multiplying, we get:

14/17 = 3/3 = 42/51

Now, we take 42/51 x 2/3 to find out how much David has now, which is 28/51

Before he received the $76, David had 3/17 = 9/51

So now, we just take 28/51 (David’s current) – 9/51 (David’s Before) = 19/51

19u = $76

28u = $(76/19) x 28 =$ 112 !

If this answer was helpful, please like and accept it as correct 🙂 Hope this helped!

-Michelle (www.dingletutors.com)

D : F : Total

Before 3 : 14 : 17

(×3) 9 : 42 (×3)

+ 76 | |

After 2 : 3

(×14) 28 : 42 (×14)

28u – 9u = 19u

19u = 76

1u = 4

David’s amt now = 28u

= 28 × $4

= $112 (ans)

This is a Before After question.

Before | transfer | after | |

David | 3u | + 76 | 3u + 76 |

Faizal | 14u | 14u | |

Total | 17u |

(3u + 76) / 2 = 14u / 3

9u + 228 = 28u

228 = 28u – 9u

19u = 228

1u = 228 ÷ 19 = 12

3u = 12 × 3 = 36

36 + 76 = $112

David : Faizal : Total

3 : 14 : 17

9 units : 42 units ; 51 units

(2/3) x 42 = 28

28 – 9 = 19

19 units = 76

1 unit = 76/19 = 4

4 x 9 + 76 = 112

Ans : $112.

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