# Question

David had 3/17 of the total amount of money he and Faizal had. After David’s father gave him \$76, he had 2/3 as much money as Faizal. How much money did David have now?

Hi Logan77!

To solve this, you have to make the denominators the same.

First, we find Faizal’s amount in fractions:

1-3/17 = 14/17

We know 14/17 is equal to 3/3 for Faizal’s case, since his amount did not change.

Hence, through cross-multiplying, we get:

14/17 = 3/3 = 42/51

Now, we take 42/51 x 2/3 to find out how much David has now, which is 28/51

So now, we just take 28/51 (David’s current) – 9/51 (David’s Before) = 19/51

19u = \$76

28u = \$(76/19) x 28 =\$ 112 !

-Michelle (www.dingletutors.com)

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D  :  F    :  Total

Before    3  :  14   :  17

(×3)    9  :  42      (×3)

+ 76   |        |

After      2   :   3

(×14)   28  :   42  (×14)

28u – 9u = 19u

19u = 76

1u =  4

David’s amt now = 28u

= 28 × \$4

= \$112 (ans)

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This is a Before After question.

 Before transfer after David 3u + 76 3u + 76 Faizal 14u 14u Total 17u

(3u + 76) / 2   = 14u / 3

9u + 228 = 28u

228 = 28u – 9u

19u = 228

1u = 228 ÷ 19 = 12

3u = 12 × 3 = 36

36 + 76 = \$112

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David : Faizal : Total
3 : 14 : 17
9 units : 42 units ; 51 units

(2/3) x 42 = 28
28 – 9 = 19
19 units = 76
1 unit = 76/19 = 4
4 x 9 + 76 = 112

Ans : \$112.

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