Last.year peter was.five times as old as his son roy..given that their total ages now are 38 years. How old will peter be when he is thrice as.old as his son ?
STUCK ON HOMEWORK?
ASK FOR HELP FROM OUR KIASUPARENTS.COM COMMUNITY!
Question
Answer

This is a Before After question.
Before | Transfer | After | now | |
Peter | 5u | +1 | 5u + 1 | 31 |
Son | 1u | +1 | 1u + 1 | 7 |
Total | 6u | 6u + 2 |
6u + 2 = 38
6u = 38 – 2 = 36
1u = 36 ÷ 6 = 6
6 + 1 = 7
5u = 5 × 6 = 30
30 + 1 = 31
7 + 5 = 12
31 + 5 = 36
Last two steps 7 + 5 can you exp ?

I simplified it by using trial and error method.
Now 7 31
1 year 8 32
2 years 9 33
3 years 10 34
4 years 11 35
5 years 12 36
Alternatively, you may use the cross multiplcation method.
(7 + 1u)/1 = (31 + 1u)/3
21 + 3u = 31 + 1u
3u – 1u = 31 – 21
2u = 10
1u = 10 ÷ 2 = 5
Alternatively, you may use the Difference method.
31 – 7 = 24
2u = 24
1u = 24 ÷ 2 = 12
12 – 7 = 5 years
31 + 5 = 36 years old
Last year —
Peter : 5 units
Roy : 1 unit
5 + 1 + 6
6 units + 2 = 38
1 unit = (38 – 2)/6 = 6
5 units = 30
Now —
Peter : 31
Roy : 7
7 x 3 = 21
31 – 21 = 10
10/2 = 5
5 + 31 = 36
Ans : 36 years old.

Last Yr Now ? Yrs later
P 5u 5u + 1 3p
R u u + 1 p
5u+1+u+1 = 38
6u = 38 – 2
= 36
1u = 36÷6
= 6
Difference btw P and R = 4u
= 24
2p = 24
1p = 12
Peter’s age = 3p
= 3 × 12
= 36 (ans)
Unit part method . Got it