LEARNConcierge

AskQ logo

STUCK ON HOMEWORK?

ASK FOR HELP FROM OUR KIASUPARENTS.COM COMMUNITY!

Question

Hi, appreciate if someone can help with this P6 math question. Thank you.

Linda, Kathy, Bob and Peter scored an average of 77 marks in a Math test. Peter’s score was 60% of Linda’s score. Bob got 5 more marks than Linda. Kathy scored 21 marks less than Linda. Find the total score of Kathy and Peter.

Answer

This is a Part Whole question. 

      Peter   Linda    Bob    Kathy    Total  
Quantity  60u 100u 100u + 5 100u – 21 360u – 16 
          308

77 × 4 = 308

360u – 15 = 308

360u = 308 + 16 = 324

160u = 160/360 × 324 = 144

144 – 21 = 123

 

 

0 Replies 1 Like ✔Accepted Answer

Hope you find this helpful.

All the best!

Subscribe to my YouTube channel for more Questions & Answers.

0 Replies 2 Likes

Hi Ski,

this question can be solved using the model I drew here : https://ibb.co/jHADuG

 

L = Linda’s marks, B = …, etc.

Linda, Kathy, Bob and Peter scored an average of 77 marks in a Math test -> ( L + K + B + P ) / 4 = 77

 Peter’s score was 60% of Linda’s score -> P = L * (60/100) = 0.6L

Bob got 5 more marks than Linda -> B = L + 5

Kathy scored 21 marks less than Linda -> K = L – 21

The above 3 means:

( L + K + B + P ) / 4 = 77  -> ( L + L – 21 + L + 5 + 0.6L )/4  = 77 -> ( 3.6L – 16 ) = 308  -> L = 90

K + P = L -21 + 0.6L = 1.6L -21 = 1.6*90 – 21 = 123

If this answer helped, please like and accept it so we can help others 🙂 !

-Michelle (www.dingletutors.com)

0 Replies 1 Like
LEARNConcierge