# Question

Hi, appreciate if someone can help with this P6 math question. Thank you.

Linda, Kathy, Bob and Peter scored an average of 77 marks in a Math test. Peter’s score was 60% of Linda’s score. Bob got 5 more marks than Linda. Kathy scored 21 marks less than Linda. Find the total score of Kathy and Peter.

This is a Part Whole question.

 Peter Linda Bob Kathy Total Quantity 60u 100u 100u + 5 100u – 21 360u – 16 308

77 × 4 = 308

360u – 15 = 308

360u = 308 + 16 = 324

160u = 160/360 × 324 = 144

144 – 21 = 123

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All the best!

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Hi Ski,

this question can be solved using the model I drew here : https://ibb.co/jHADuG

L = Linda’s marks, B = …, etc.

Linda, Kathy, Bob and Peter scored an average of 77 marks in a Math test -> ( L + K + B + P ) / 4 = 77

Peter’s score was 60% of Linda’s score -> P = L * (60/100) = 0.6L

Bob got 5 more marks than Linda -> B = L + 5

Kathy scored 21 marks less than Linda -> K = L – 21

The above 3 means:

( L + K + B + P ) / 4 = 77  -> ( L + L – 21 + L + 5 + 0.6L )/4  = 77 -> ( 3.6L – 16 ) = 308  -> L = 90

K + P = L -21 + 0.6L = 1.6L -21 = 1.6*90 – 21 = 123

If this answer helped, please like and accept it so we can help others 🙂 !

-Michelle (www.dingletutors.com)

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