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**Concept****Any two points at the same height in a liquid have the same pressure.**

Thus, the pressure at height *k* in the right column, *P-right-k*, will be equal to the pressure at height *k* in the left column, *P-left-k*. In short,** P-right-k = P-left-k** —- (1)

**Left column**

The pressure at the left column is caused by the mercury above. Thus, **P-left-k = (h-k) ****cmHg** —- (2)

**Right column**

Substituting (2) in (1), we get*P-right-k = (h-k)* cmHg

Since the pressure at the surface of the right mercury column is due to enclosed air, the enclosed air pressure = **( h-k) cmHg//**

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