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This is a fractional transfer question. 

LCM(left)

­

2/3

   Before transfer After  
Pen 3u -1u 2u  
Notebook  298 – 3u -63  235 – 3u  
Total 298      

2u = 235 – 3u

2u + 3u = 235

5u = 235

1u = 235 ÷ 5 = 47

3u = 3 × 47 = 141 (pen)

298 – 141 = 157 notebook 

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