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Question

P6 fraction .

There are 1174 people at fun fair. 2/5 of the males are men and 4/7 of the females are women. There are 78 more boys than girls. How many more women than men are there at the funfair?

Answer

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males : 5u
men : 2u
boys : 3u

females : 7p
women : 4p
girls : 3p

5u + 7p ——- 1174
15u + 21p ——- 3522
3u – 3p ——- 78
15u – 15p ——- 390
36p ——- 3132
1p ——- 87
3u – 3 x 87 = 3u – 261 ——- 78
1u ——- (78 + 261)/3 = 113
4p – 2u ——- 4 x 87 – 2 x 113 = 122

Ans : 122 more women.

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This is a Simultaneous Equation.

  Adult Child Total Child x 7 Total x 3 CR
Male 2 3 5 21 15 36
Female 4 -3 7 -21 21 0
Total   78 1174 546 3522 4068

36 Male = 4068

1 Male = 4068 ÷ 36 = 113

2 Male = 2 x 113 = 226 (Men)

5 Male = 5 x 113 = 565

7 Female = 1174 – 565 = 609

1 Female = 609 ÷ 7 = 87

4 Female = 4 x   87 = 348 (Women)

348 – 226 = 122  

 

 

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