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1 – 1/5 = 4/5 ——-> 480
1/5 ——-> 120
5/8 of the water from container B ——-> 580 – 120 = 460
8/8 of the water in container B at first ——-> (460/5) x 8 = 736

Ans : 736 ml.

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The is a Before After question.

  After Transfer After Transfer before
A 580 + 460

1a = 120ml

+4a 5a
B 8b -5b 3b    

4a = 480

1a = 480÷ 4 = 120 ml

580 – 120 = 460

5b = 460

1b = 460 ÷5 = 92

8b = 8 x 92  = 736 ml

 

 

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Hope this answer your question.

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736ml.

 

Since 480ml of water being used led to the volume in Container A to decrease to 1/5 from full, we can determine that the vol. left in Container A is 120ml.

When 5/8 of water is poured from B to A, water in A became 580ml

5/8 of water from B = 580 – 120 (original amount in A) =460

amount of water in B at first is 8/8, so (460/5)x8=736

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