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Hi, we need help for this qn. Tq!

_________

Mr Suray had some money. He spent  $154 on a jacket and 3/8 of the remainder on a shaver. He had 1/3 of his money left.

a) what fraction of the money did he spend in the jacket?

b) how much money did he have at first?

Can someone explain via both  branching and model method?

 

Answer

This is a problem sum that requires the drawing of a model for the student to be able to visualise better and hence solve the problem with ease. We do not use the branching method for this as it is not suitable. In order of the branching method to be used, effectively, the ‘remainder’  must be of a known fraction value. In the above problem on the other hand, has an unknown remainder. Hope this can help to clarify a little.

To solve:

We call this the Long Box Model, we can see that after spending $154 on the jacket, Mr Suray is going to spend another 3/8 of the the remainder of his money on the shaver, hence, we cut the ‘remainder’ into 8 units. And 3 units represent what he spent on the shaver. The leftover 5 units represent 1/3 of his original sum of money. 

With that, we deduce that he originally had 15 units of money, since 3/3 of his money represents 15 units.

So, since he originally had 15 units of money, and 8 units belong to the ‘remainder’, the other 7 units come to represent the ‘$154’.

Hence we can solve the question with the following steps as seen above (:

 

 

We provide coaching for small, focus groups of students at Future Achievers Hub at Tampines Junction.

Do check out:

www.futureachievers.com.sg

or call us at +65 83325521,

for more info and sign up for Free Classes now!

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This is a problem sum that requires the drawing of a model for the student to be able to visualise better and hence solve the problem with ease. We do not use the branching method for this as it is not suitable. In order of the branching method to be used, effectively, the ‘remainder’  must be of a known fraction value. In the above problem on the other hand, has an unknown remainder. Hope this can help to clarify a little.

To solve:

We call this the Long Box Model, we can see that after spending $154 on the jacket, Mr Suray is going to spend another 3/8 of the the remainder of his money on the shaver, hence, we cut the ‘remainder’ into 8 units. And 3 units represent what he spent on the shaver. The leftover 5 units represent 1/3 of his original sum of money. 

With that, we deduce that he originally had 15 units of money, since 3/3 of his money represents 15 units.

So, since he originally had 15 units of money, and 8 units belong to the ‘remainder’, the other 7 units come to represent the ‘$154’.

Hence we can solve the question with the following steps as seen above (:

 

 

We provide coaching for small, focus groups of students at Future Achievers Hub at Tampines Junction.

Do check out:

www.futureachievers.com.sg

or call us at +65 83325521,

for more info and sign up for Free Classes now!

0 Replies 0 Likes

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My previous answer for a) was not right. Edited below.

I am not too sure with branching method. I did model diagram method. 

Jacket cost $154, need to find how many units for jacket.

Shaver is 3/8 remainder. Means 5/8 remainder left is 1/3 of his before money.

So jacket and shaver are 2/3 of his before money. Or 10 units from the  model. Since shaver is 3 units, so jacket is 7 units.

7u = $154

1u = $22

B) 15u × $22 = $330 he had at first.

A) fraction for jacket will be 154/330 = 77/165

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Can the below answer be further simplified to 7/15 ?

fraction for jacket will be 154/330 = 77/165 =7/15 

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This is Part whole question. 

  Jacket  Shaver  Left  total 
Quantity  154 3u 5u 154 + 8u
      1 3

5u/ 1 = (154 + 8u) / 3

15u = 154 + 8u

15u – 8u = 154

7u = 154

1u = 154 ÷ 7 = 22

b)

8u = 22 × 8 = 176

176 + 154 = 330

a)

154/ 330 = 77/165

 

Note 

A Branching question has 2 fractions.

Eg 1/3 on Jacket and 3/8 of the remainder on Shaver.

This question is just a Part Whole question because it started with  a Number $154.

 

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a)
Branching method :
his money – 154 (jacket)
                    – remainder – 3/8 (shaver)
                                           – 5/8 = 1/3 of his money

154 + 3/8 of the remainder = 2/3 of his money = 10/8 of the remainder
remainder = [154/(10 – 3)] x 8 = 176
154/(154 + 176) = 77/165

 

Model method :
154 + 1 unit + 1 unit + 1 unit + 1 unit + 1 unit + 1 unit + 1 unit + 1 unit

1/3 of his money = 5 units
2/3 of his money = 10 units = 154 + 3 units
1 unit = 154/(10 – 3) = 22
22 x 8 = 176
154/(154 + 176) = 77/165

(b)
154 + 176 = 330

Ans : (a) 77/165; (b) $330.

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