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Question

 Mrs Tan and Mrs Tay made a total of 84 doughnuts. Mrs Tan gave 1/3 of her doughnuts to Mrs Tay. Mrs Tay then gave 2/5 of the total number  of doughnuts she had to Mrs. Tan. In the end each of them had the same number of doughnuts. How many doughnuts did Mrs. Tan make at first ?

Answer

84/2 = 42
1- (2/5) = 3/5 ——-> 42
2/5 ——-> 28
1 – (1/30 = 2/3 ——-> 14
1/3 ——-> 7
7 + 14 = 21
or
Working backwards,
Mrs Tan :
42 – 28 = 14
14 + 7 = 21
Mrs Tay :
42 + 28 = 70
70 – 7 = 63

Ans : 21 doughnuts.

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This is a Multiple transfer question.

LCM (Left)

2/3 = 6/9

3/5 = 6/10

   After  transfer Before  Transfer  Before 
Tay    6u +4u 10u – 1u 9u
Tan 6u -4u 2u + 1u 3u

9u + 3u = 12u

12u = 84

1u = 84 ÷ 12 = 7

3u = 3 × 7 = 21 

 

 

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could you pl. explain how you get the transfer +4 -4 values ?

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