# Question

Ali bought 3 times as many toy cars as game cartridges . He spent \$1615 altogether .
A game cartridge is \$15 more than a toy car. The total cost of all the toy cars was \$425 more than the total cost of all the game cartridges.  Find the cost of a game cartridge. (2017 PSLE Question )

toy cars : 3u
cost : 1p

game cartridges : 1u
cost of a game cartridges : 1p + 15

3u x 1p = 3up (total cost of all toy cars)
1u x (1p + 15) = 1up + 15u (total cost of all the game cartridges)

3up + 1up + 15u = 4up + 15u ——- 1615
3up – 1up – 15u = 2up – 15u ——-> 425
4up – 30u ——-> 850
4up + 15u – (4up – 30u) = 45u ——-. 1615 – 850 = 765
1u ——-> 765/45 = 17
2 x 17 x p – 15 x 17 = 34p – 255 ——-> 425
p ——-> (425 + 255)/34 = 20
1p + 15 = 20 + 15 = 35

Ans : \$35.

0 Replies 0 Likes ✔Accepted Answer

This is a Quantity Each Product question.

 Quantity Each Product Car 3u 1020 Game 1u 595 Total 1615

1615 – 425 = 1190

1190 ÷ 2 = 595

595 + 425 = 1020

595 / 1u  = 1020 / 3u   +  15

595 / 1u   –  340 / 1u = 15

595 – 340 = 15u

15u = 255

1u = 255  ÷ 15 =  17

595 ÷ 17 = 35

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